In the RER formula, what exponent is applied to body weight?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $25.99Unlock all

Prepare for the Veterinary III CFE Exam with focused study material and interactive quizzes. Use detailed flashcards and multiple choice questions for a comprehensive review. Equip yourself with the knowledge and confidence needed to excel in your study sessions and excel in your assessment!

Multiple Choice

In the RER formula, what exponent is applied to body weight?

Explanation:
Metabolic rate scales with body size in a non-linear way, so the resting energy needs are not simply proportional to weight. The standard resting energy requirement uses body weight raised to the three-quarters power, a reflection of allometric scaling (Kleiber’s law). This means the exponent applied to body weight is 0.75, giving the commonly used formula RER = 70 × BW^0.75 (with BW in kilograms). Using 0.75 fits the observed scaling of metabolic rate across different animal sizes, whereas 1.0 would imply direct proportionality to weight, and 0.25 or 0.5 would not align with the typical veterinary nutrition model.

Metabolic rate scales with body size in a non-linear way, so the resting energy needs are not simply proportional to weight. The standard resting energy requirement uses body weight raised to the three-quarters power, a reflection of allometric scaling (Kleiber’s law). This means the exponent applied to body weight is 0.75, giving the commonly used formula RER = 70 × BW^0.75 (with BW in kilograms). Using 0.75 fits the observed scaling of metabolic rate across different animal sizes, whereas 1.0 would imply direct proportionality to weight, and 0.25 or 0.5 would not align with the typical veterinary nutrition model.

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy